the bace of paralelegram is doble of its hight if the are is 512 sq.m then find the bace and hight
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area of parallelogram = base * height
let the height x so base is 2x
x*2x=512
2xsquare=512
xsquare=256
- x=16m
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ATQ, the bace of the paralelegram is doble of its hight.
let the hight of the paralelegram be x.
there4 its bace = 2x
nao formula to find the area of a paralelegram is bace × hight
➡ bace × hight = 512m²
➡ 2x × x = 512m²
➡ 2x² = 512m²
➡ x² = 512/2
➡ x² = 256
➡ x = √256
➡ x = 16m
hence, the bace of the paralelegram is = 2x = 2 × 16 = 32m
and hight of the paralelegram = x = 16m
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