the bag contains 12 balls of which X number of balls are white if 6 more white balls are put in the bag the probability of drawing a white ball will be double than that when the probability of drawing a white ball random .then the value of x
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Answered by
3
Answer:
Step-by-step explanation:
no of balls=12
no of white balls =x
p(white ball) = no. of favourable outcomes/no of total possible outcomes
= x/12----(1)
2)
if 6 more white balls are put in the bag
no of total balls = 18
no of white balls =x+6
p(white balls)= (x+6)/18---(2)
therefore
(x+6)/18 = 2*x/12
(x+6)/18 =x/6
x+6 = 18x/6
x+6=3x
6=3x-x
6=2x
2x=6
x=6/2
x=3
yashwanthg195:
another method
Answered by
0
Hi..
total balls = 12
white balls = x
probability = x/12______(1)
if 6 are added,
white balls = x+6
total = 18
probability = x+6/18_______(2)
From 1 and 2
ATQ,
▪
▪12x + 72 = 36x
▪24x = 72
▪x = 72/2
#tq
total balls = 12
white balls = x
probability = x/12______(1)
if 6 are added,
white balls = x+6
total = 18
probability = x+6/18_______(2)
From 1 and 2
ATQ,
▪
▪12x + 72 = 36x
▪24x = 72
▪x = 72/2
#tq
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