Question

where did the 2x-3y =8 intersect at x axis?

Answer 1

Answer: it intersect the x axis at (4,0) .

Step-by-step explanation: use intercept form 2x-3y= 8 . Divide both sides by 8 then x/4-3y/8=1 it means it x intercept = 4 and y intercept= -8/3. I hope it help you . Mark answer as brainlist.

Answer 2

Answer:

The line 2x-3y =8 intersect the x- axis at (4,0).

Step-by-step explanation:

Using intercept form of line, we get

$2x-3y = 8$

Divide both sides by 8 , we get

$\frac{2x}{8} -\frac{3y}{8} =\frac{8}{8}$

$\frac{x}{4} + }\frac{y}{\frac{-8}{3} } = 1$

$4 = x-intercept\\\frac{-8}{3} = y- intercept$

Therefore,the line would cut the x-axis at (4,0)

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