Question

The ball is dropped from the top of high tower distance traveled by the ball in 2nd second of its motion is (g=10m/s^2)

Answer 1

Answer:

The answer will be 20 m

Explanation:

According to the problem the ball is dropped and covered a distance within 2 second

let the distance covered is s within time t = 2 sec

Therefore,

s = 1/2 g x t^2 = 1/2 x 10 x (2)^2 = 20 m

hence the distance covered in 2 sec is 20 m