Question

the ball is projected up from ground with speed 30 m 30 m/sec. what is the average velocity for time 0 to 4 sec?

Answer 1

Hey dear,


◆ Answer -
v(avg) = 10 m/s

◆ Explaination -
# Given -
u = -30 m/s
t = 4 s

# Solution -
Final velocity is given by-
v = u + gt
v = -30 + 10×4
v = 10 m/s

Average velocity is given by -
v(avg) = (v - u) / t
v(avg) = (10 + 30) / 4
v(avg) = 10 m/s

Average velocity of the ball is 10 m/s.

Hope this helps you...

Answer 2

Answer:

Average velocity of the ball is 10 m/s

Step-by-step explanation :

Initial velocity [ u ] = 30 m/s

Time [ t ] = 4 sec

Since we know,

Average velocity = ( Total Distance ) / ( Total Time )

We also know that

S = $ut+\frac{1}{2}at^{2}$

where,

S = Distance

u = Initial velocity

a = acceleration

t = time

Substituting the known values,

Taking a = 10 m/s²

The acceleration due to gravity is taken as negative when the ball in upward direction therefore we take the acceleration  = - 10 m/s²

S = $30*4+\frac{1}{2}(-10)(4)^{2}$

S = 120 + ( - 80 )

S = 40 m

Putting the value of in the formula for average velocity :

Average velocity = 40 / 4

Average velocity = 10 m / s

Hence,

Average velocity of the ball is 10 m/s

Average velocity is given by -

v(avg) = (v - u) / t

v(avg) = (10 + 30) / 4

v(avg) = 10 m/s

Average velocity of the ball is 10 m/s.

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