the base and altitude of a triangle are in the ratio 3 ratio 4 and its area is a 96 CM square find its base and attitude
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let base n attitude be 3x, 4x
area = 96cm
1/2*b*h=96
1/2*3x*4x=96
12x^2=96/2
=48
x^2=48/12
x^2=4
x=√4
x=2
base =3*2=6
attitude =4*2=8
area = 96cm
1/2*b*h=96
1/2*3x*4x=96
12x^2=96/2
=48
x^2=48/12
x^2=4
x=√4
x=2
base =3*2=6
attitude =4*2=8
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