Question

The base and height of a parallelogram are in 1:3 it's area is 12sq cm find base and height

Answer 1

Answer:

Step-by-step explanation:

Suppose the base is x cm

The base and height are in the ratio of 1:3 ,

So the height could be 3 x cm

Given that the area of the parallelogram is 12 cm²

∴ Area = h × b

∴ 12 = x × 3 x

∴ 12 = 3 x²

∴ 4 = x²

∴ √4 = x

∴ ±2 cm = x

Length cannot be negative

So x = 2 cm

So base = 2 cm and height = 6 cm

Answer 2

Base of parallelogram = 2 cm

Height of parallelogram = 6 cm

Step-by-step explanation:

We are given that the ratio of base and height of a parallelogram is 1 : 3 .

Let base of parallelogram be $1 \times x$ = $x$

and height of parallelogram be  $3 \times x$ = $3x$

Now, Area of parallelogram = Base $\times$ Height

                     12 $cm^{2}$        =  $x \times 3x$

                       12   =  $3x^{2}$

                        $x^{2}$ = 12/3 = 4

                        x = $\pm 2$

But since base or height can't be negative so $x$ = 2

Therefore, base of parallelogram = $x$ = 2 cm

                  height of parallelogram = $3x$ = $3 \times 2$ = 6 cm