The base and height of a triangle are in the ratio 2:3 and it's area is 216 cm spuare . Find the area of the triangle
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Given,
Base:height = 2:3
Area of the triangle = 216 cm^2.......(1)
Assumptions,
Let the base of the triangle be 2x.....(2)
Let the height of the triangle be 3x...(3)
We know,
Area of the triangle = 1/2*b*h...........(4)
We have,
Area of the triangle = 216 cm^2
From (1) already given,
1/2*b*h = 216
From (4) we know,
1/2*2x*3x = 216
From (2) and (3) our assumptions,
Solving,
3*x^2 = 216
x^2 = 72
x = 6*root(2)
So, length = 2x = 12*root(2) cm
Breadth = 3x = 18*root(2) cm
Base:height = 2:3
Area of the triangle = 216 cm^2.......(1)
Assumptions,
Let the base of the triangle be 2x.....(2)
Let the height of the triangle be 3x...(3)
We know,
Area of the triangle = 1/2*b*h...........(4)
We have,
Area of the triangle = 216 cm^2
From (1) already given,
1/2*b*h = 216
From (4) we know,
1/2*2x*3x = 216
From (2) and (3) our assumptions,
Solving,
3*x^2 = 216
x^2 = 72
x = 6*root(2)
So, length = 2x = 12*root(2) cm
Breadth = 3x = 18*root(2) cm
Swarup1998:
216/3 = 72
Answered by
0
Base:height = 2:3
Area of the triangle = 216 cm^2.......(1)
Assumptions,
Let the base of the triangle be 2x.....(2)
Let the height of the triangle be 3x...(3)
We know,
Area of the triangle = 1/2*b*h...........(4)
We have,
Area of the triangle = 216 cm^2
From (1) already given,
1/2*b*h = 216
From (4) we know,
1/2*2x*3x = 216
From (2) and (3) our assumptions,
Solving,
3*x^2 = 216
x^2 = 72
x = 6*root(2)
So, length = 2x = 12*root(2) cm
Breadth = 3x = 18*root(2) cm.
Thanks!
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