the base and height of a triangle are in the ratio 3:4 and its area is 96 cm sq .find its base and height
Answers
Answered by
5
Let assume base =3x
Height =4x
Area of triangle =1/2 xbxh
=1/2*3x*4x=6x^2
Atq
Area =96
6x^2=96
X^2=96/6=16=>x=4
Base =3x4=12cm
Height =4x4=16cm
Answered by
2
Area of a triangle is = 1/2×b×h
b= base
h = height
now
b:h
= 3:4
let. b =3x
h=4x
=>area∆= 1/2×3x×4x
=1/2×12x
=6x^2
and area∆is =96 cm ^2. given
=>96= 6x^2
x^3 =96/6
=32/2
=16
x=4
b=3×4=12 cm
h=4×4=16cm
b= base
h = height
now
b:h
= 3:4
let. b =3x
h=4x
=>area∆= 1/2×3x×4x
=1/2×12x
=6x^2
and area∆is =96 cm ^2. given
=>96= 6x^2
x^3 =96/6
=32/2
=16
x=4
b=3×4=12 cm
h=4×4=16cm
Anonymous:
hmm
i am in b.sc
hi
first of all u r not cute
and secondly this is not u in the pic
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