Question

. The base and hypotenuse of a right
triangle are 20 cm and 29 cm. The area of
a triangle is​

Answer 1

Answer:

Base of triangle = 20 cm

Hypotenuse of triangle = 29

Height of triangle = ?

In a triangle,

Hypotenuse² = Base² + Height²..........

(Pythagoras theorem)

29² = 20² + h²

29² - 20² = h²

h² = 881 - 400

h² = 441

h = √441

h = 21

Therefore, height of triangle = 21

We know that,

Area of triangle = 1/2 × b × h

= 1/2 × 20 × 21

= 10×21

= 210

Therefore, the area of triangle = 210 cmsq

Answer 2

Given :

• Base and Hypotenuse of a right angled triangle is 20 cm and 29 cm respectively .

To Find :

• Area of Triangle .

Solution :

Firstly we will find the height of Triangle :

By Using Pythagoras Theorem :

$\longmapsto\tt{{(H)}^{2}={(B)}^{2}+{(P)}^{2}}$

$\longmapsto\tt{{(29)}^{2}={(20)}^{2}+{(P)}^{2}}$

$\longmapsto\tt{841=400+{P}^{2}}$

$\longmapsto\tt{841-400={P}^{2}}$

$\longmapsto\tt{\sqrt{441}=P}$

$\longmapsto\tt\bf{21=P}$

So , Height of Triangle is 21 cm...

Now ,

$\longmapsto\tt{Base=20\:cm}$

$\longmapsto\tt{Height=21\:cm}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:\triangle=\dfrac{1}{2}\times{b}\times{h}}$

Putting Values :

$\longmapsto\tt{\dfrac{1}{{\cancel{2}}}\times{{\cancel{20}}}\times{21}}$

$\longmapsto\tt{10\times{21}}$

$\longmapsto\tt\bf{210\:{cm}^{2}}$

So , The Area of Triangle is 210 cm² ...