Question

The base angle of an isosceles triangle is 15° more than its vertex angle . Find all the angles.​

Answer 1

Let vertical angle of the isosceles triangle = x°

∴ Each base angle = x + 15°

X + 15° + x + 15° + x° = 180°

(Sum of angles of a triangle)

⇒ 3x + 30° = 180°

⇒ 3x = 180° - 30° = 150°

∴ x = 150°/3 = 50°

Hence vertical angle = 50°

and each base angle = 50° + 15° = 65°

Answer 2

Answer:

Answer in the given attachment

Mark my answer as the brainliest.