Question

the base BC of an equilateral triangle ABC lies on y-axis. the coordianates of point C are (0,-3). the origin is the mid-point of the base. find the coordinates of the points A and B. also find the coordinates of another point D such that BACD is a rhombus.

Answer 1

first find D wid midpoint formula
then substitute all the values in slope of line method
then find equation of that line by point slope form you will get the coordinates of rhombus BACD.......

Answer 2

Answer:

Step-by-step explanation:

since origin (0,0) is the mid point of base BC

let coordinates of point B(x1,y1)

C(0,-3)

0=(x1+0)/2 and     0=(y1 -3)/2

x1=0  and y1=3

B(0,3)

length of base BC=6

point A will lie on x axis

AB=6 (equilateral triangle)

OA=sqrt(AB^2 - BO^2)   by pythogorous theorem

OA=sqrt(36 - 9)

OA=3sqrt3

cordinates of point A=(3,0)

                              and(-3,0)

D=(-3,0)

and (3,0)