Question

the base diameter of a cone 16m and its height is 17m then find i) C.S.A. ii) T.S.A

Answer 1

1.CSA of cone =pi×r×l
we have find the slant height i.e..root of height square +radius square.....
then we shold substitute in the formula....
2.TSA of cone =pi ×r(r+l)
we shold take pi value as22/7 and substitute all the values

Answer 2

Answer ⤵️

Diameter of the cone= 16 m

Radii of the cone= 16/2= 8 m

i) C.S.A= πrl

$\frac{22}{7} \times 8 \times 17 \\ = \frac{2992}{7} \\ = 427.42 \: {cm}^{2}$

ii) T.S.A= πr(l+r)

$\frac{22}{7} \times 8(17 + 8) \\ = \frac{22}{7} \times 8 \times 25 \\ = \frac{4400}{7} \\ = 628.57 \: {cm}^{2}$

So,

C.S.A= 427.42 cm²

T.S.A= 628.57 cm²

Step-by-step explanation:

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