Question

The base of a box has a parameter 20m and its height is 8m. if the height is 3m more than one of it base sides, find its surface area.​

Answer 1

210 cm²

Step-by-step explanation:

Q.

The base of a box has a perimeter 20 m and its height is 8 m. If the height is 3 m more than one of it base sides, find its surface area

Solution -

If height is 3 less than its base sides, so base sides will be 8 m - 3 m = 5m

Base's sides are length (l) and breadth (b).

Now,

l = 5 m

b = 5 m

h = 8 m

Surface area (T. S. A) = 2 (lb + bh + lh)

= 2 {(5×5) + (5×8) + (5×8)} m²

=> 2 (25 + 40 + 40) m²

=> 2(105) m²

=> 210 m²

Hence Surface area of box = 210 cm²

Note :-

Here,

T. S. A = Total Surface area

l = length

b = breadth

h = height

To remember :-

T. S. A of cuboid = 2 (lb + bh + lh)

C. S. A. of cuboid = 2(l + b)h

T. S. A. of cube = 6a²

L. S. A of cube = 4a²

hope it helps.