The base of a cylindrical vessel measures 300cm2, water is poured into it upto a
depth of 6cm. Calculate the pressure of water on the base of the vessel. (g=10 m/s2;
density of water = 1000 kg/m3)
TNSCERT Class 9 General Science Ch 7 Liquids
Answers
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We know that P = ρgh
where,
ρ = density of water = 1000 kg/m³
g = acceleration due to gravity = 10 m/s²
h = height = 6 cm = 0.06 m
As P = ρgh
= 1000 x 10 x 0.06
= 600 kg/ms²
= 600 Pa
threfore, pressure = 600 Pa
where,
ρ = density of water = 1000 kg/m³
g = acceleration due to gravity = 10 m/s²
h = height = 6 cm = 0.06 m
As P = ρgh
= 1000 x 10 x 0.06
= 600 kg/ms²
= 600 Pa
threfore, pressure = 600 Pa
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