Question

The base of a parallelogram is (5x+4).If the area is 25x^2-16 then its height​

Answer 1

Answer:

h = 5x-4

Step-by-step explanation:

Area : 1/2*b*h

: 25x^2-16

Base : 5x+4

Height:25x^2-16/5x+4

: 5x-4

Answer 2

GivEn:

• Base of a parallelogram = (5x + 4)

• Area of parallelogram = 25x² - 16

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To find:

• Height of parallelogram.

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SoluTion:

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$\bf \underline{\bigstar\;As\; we\; know\; that,}$

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$\star\;{\boxed{\sf{Area\;of\; parallelogram, A = bh}}}$

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Therefore,

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$:\implies\sf 25x^2 - 16 = (5x + 4)h$

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$:\implies\sf h = \dfrac{25x^2 - 16}{5x + 4}$

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$:\implies\sf h = \dfrac{ \cancel{(5x + 4)}(5x + 4)}{ \cancel{5x + 4}}$

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$:\implies{\underline{\boxed{\sf{\pink{h = 5x + 4\;cm}}}}}\;\bigstar$

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$\therefore$ Hence, Height of Parallelogram is (5x + 4) cm.

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★ Additional Information:

• Area of Parallelogram using Trigonometry = [A = ab sin (x)]

• Area of Parallelogram using base and height = [ A = b × h ]

• Area of Parallelogram using Diagonals = [ A = ½ × $\sf d_1$ × $\sf d_2$ sin (y)]