the base of a right pyramid is an equilateral triangle each side of which is 6 ×root 3cm long and height is 4 cm find the total surface area of the pyramid in cm square
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Side of a right pyramid is 6 × root 3 cm
Height is 4 cm
Area of the pyramid = root 3 /4 × a^2
= root 3 /4 × 6 × root 3
= 3 × root 3 × root 3 /2
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Height is 4 cm
Area of the pyramid = root 3 /4 × a^2
= root 3 /4 × 6 × root 3
= 3 × root 3 × root 3 /2
Hope this help you
please mark as brainlist
please please please
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