The base of a right triangle is 6cm and hypotenus is 10cm what will be the area
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Applying Pythagoras theorem
H^2=P^2+B^2
P^2 = 10^2-6^2
P^2 = 100-36
P^2 = 64
P = √64
P = 8cm
Area of Triangle = 1/2 × base × height
1/2 × 6 × 8
24 cm^2
H^2=P^2+B^2
P^2 = 10^2-6^2
P^2 = 100-36
P^2 = 64
P = √64
P = 8cm
Area of Triangle = 1/2 × base × height
1/2 × 6 × 8
24 cm^2
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