Question

the base of a triangle is 24 cm and the corresponding altitude in 16 cm the area of a rhombus is equal to the area of a triangle if one of the diagonals of the Rhombus is 20 cm find the length of the Other diagonal

Answer 1

area of triangle = base * height = 24*16=400

area of rhombus = product of the two diagonals

as area of triangle is equal to area of rhombus so;

20* 2nd diagonal = 400

so; 2nd diagonal = 400/20

= 20

Answer 2

given base of triangle=24cm

and and height equal to 16cm

so area of triangle is

$1 \div 2 \times 24 \times 16 = 132$

according to question

area of triangle equal to area of Rhombus

therefore,

$1 \div 2 \times d1 \times d2 = 132$

$1 \div 2 \times 20 \times d1 = 132 \\ d1 = 13.2cm$