Question

the base of a triangle is 4cm longer than it's altitude if the area of a triangle is 48sq.cm then find it's base and altitude​

Answer 1

Answer:

let base = b and altitude= h.

now, b= h+4

area of triangle = 1/2 × b×h

48 = 1/2 x (h+4) x h

96 = h^2+ 4h

0 = h^2 + 4h -96

0 = h^2+ 12h - 8h -96

0 = h(h+12) - 8(h+12)

0 = (h+12) (h-8)

so either h+12 = 0 or h-8 =0

so h= -12 cm or h= 8 cm.

as length cannot be negative

so h= 8 cm and b=h+4 = 12cm