Question

The base of a triangle is 8cm. If altitude of triangle is two times of its base, then find out the area of triangle.

Answer 1

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$\huge\red{64 sq.cm}$

$<center><font size="6" color="purple">SOLUTION</font></center>$

$<b>BASE= 8 CM</b>$

$<b>ALTITUDE= 16 ( TWICE OF BASE)</b>$

$<b>AREA OF TRIANGLE</b>$

$= >\huge\frac{1}{2} \times base \times height$

$= >\huge\frac{1}{2} \times 8 \times 16$

$<b>REDUCE THE FRACTIONS</b>$

$= >\huge 1\times 8 \times 8$

$= >\huge{ 64sq \: cm}$

Answer 2

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ANSWER :

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The Base of the Triangle, b = 8 cm

The Height of the triangle, h = 2b

= 2 × 8

= 16 cm

The Area of the triangle, A = ?

We know that ,

$area \: of \: triangle \: = \frac{1}{2} \times b \times h$

From this ,,,

Area , A = 1/2 × 8 × 16

A = 4 × 6

A = 64 cm^2

The Area , A is 64 cm^2

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