the base of a triangle is divided by the altitude into two parts equal to 36 cm and 14 cm. a straight line drawn perpendicular to the base divides the area of the given triangle into two equal parts. what is the length of the smaller part of the base that is divided by this line segment?
Answers
Step-by-step explanation:
Area = ½ base · height
Area = ½ · 26 · 26K
Area = ½ · 2 · 13 · 2 · 13 · K
Area = ½ · 2² · 13² · K
Area = 2 · 13² · K
What is the area of the triangle with a (b) unit base?
Area = ½ base · height
Area = ½ · b · bK
Area = ½ · b² · K
The problem says that the larger triangle’s area is twice the size of the smaller triangle’s area:
Large Area = 2 × Small Area
2 · 13² · K = 2 × (½ · b² · K)
The 2 and ½ cancel each other on the right side
2 · 13² · K = b² · K
Divide both sides by K
2 · 13² = b²
Note: canceling the K proves that the actual ratio of height to base does not matter. We could have started with height = base in both triangles and gotten the same answer.
Reverse the sides and take the square root of both sides:
b² = 2 · 13²
b²−−√=2–√⋅13²−−−√
b=2–√⋅13
b = 13 √2
hope it's helpful to you
Answer:
plese solve
Step-by-step explanation: