The base of a triangle is half the base of a parallelogram having the same area as that of the triangle. The ratio of the corresponding heights of the triangle to the parallelogram will be:
option -
1) 1:4
2) 4:1
3) 2:1
4) 1:2
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let height of the || gm and the height of the triangle be h1 & h2 respectively
and , let the base of the ||gm be b.
then, base of the triangle=b/2
A/Q, area of triangle = area of ||gm
=> 1/2 × b/2 ×(h2) = b × (h1)
=> h2/4 = h1
=> h2/h1 = 4/1
hence, h2:h1=4:1 ans....
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