The base of a triangle lies along x =
a and is of length a. The area of
triangle isa?. The locus of vertex is
(A) (x+a)(x-3a) = 0
(B) (x-a)(x+3a)=0
(C) (x+a)(x+3a) = 0
(D) (x+2a)(x-a)=0
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Answer:
Well... that's a nice question... option a is correct
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