Question

the base of a triangle region is three times its altitude if its area is 27 square metres find its base and altitude.​

Answer 1

Answer:

let altitude be x

hence base=3x

$area \: of \: trianle = 1 \div 2 \times base \times altitude$

1/2*x*3x=27

3x^2=54

x^2=18

x=√18=√2*9=3√2

3x=3*3√2=9√2

base=9√2

altitude =3√2

Answer 2

Answer:

Base=3√18 m and Altitude=√18 m.

Step-by-step explanation:

Let the length of altitude be x meters.

Then, the length of base is 3x meters.

Area of Triangle = 1/2 × Base × Altitude (Height).

27m²= 1/2 × x m × 3x m.

54m²=3x²m².

54m²=3x²

x²=54/3=18

x=√18

Hence, the length of the altitude of the triangle is √18 m and base is 3√18 m.

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