Question

The base of an equilateral triangle ABC lies on y-axis . The coordinates of point c are(0,3) .The origin is the mid point of the base . find the coordinates of the point A&B . also find the coordinates of another point D such a that BACD is a rhombus​

Answer 1

Answer:

since origin (0,0) is the mid point of base BC

let coordinates of point B(x1,y1)

C(0,-3)

0=(x1+0)/2 and     0=(y1 -3)/2

x1=0  and y1=3

B(0,3)

length of base BC=6

point A will lie on x axis

AB=6 (equilateral triangle)

OA=sqrt(AB^2 - BO^2)   by pythogorous theorem

OA=sqrt(36 - 9)

OA=3sqrt3

cordinates of point A=(3,0)

                              and(-3,0)

D=(-3,0)

and (3,0)

Step-by-step explanation: