Question

The base of an equilateral triangle with side 2a lies along the y -axis such that the mid pt.of base is at origin .find the vertices of the triangle

Answer 1

hope this answer will help you

Answer 2

∆ABC is an equilateral, then AB = BC

AB² = BC²

use distance formula,

distance between (x₁,y₁) and (x₁,y₂) = √{(x₂-x₁)² +(y₂-y₁)²}

( h - 0 )² + ( 0 - a )² = (2a)²

h² + a² = 4a²

h² = 3a²

h = ±√3a

hence, the vertices of traingle are ( √3a, 0) , (0,a) and ( 0, -a) .