Question

The base of an equilateral triangle with side 2a lies along the y-axis such that the
mid-point of the base is at the origin. Find vertices of the triangle.​

Answer 1

कल जेल सीएम दल इस दल का दम ऑफ gm उस hl

Answer 2

Answer:

Let ABC be an equilateral triangle In equilateral triangle all sides are equal

So, AB = BC = AC = 2a

Given that

a

2a

Y

the base of equilateral triangle i.e. BC lies along the y-axis such that mid point of BC is O(0, 0)

So, OB = OC = a

: Coordinates of B = (0, a)

& Coordinates of C = (0, -a)

Step-by-step explanation:

Mark my answer as the brainliest please