the base of an isoceles triagles is 4/3 cm.the perimeter of the triangle is 4 2/5 cm.what is the length of the remaining equal sides?
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let the equal side be x cm
given
base=4/3
perimeter =42/5
A/q
4/3+x+x=42/5
4/3+2x=42/5
2x=42/5-4/3
2x=106/15
x=106/15*1/2
x=53/15
therefore remaining equal side is 53/15
given
base=4/3
perimeter =42/5
A/q
4/3+x+x=42/5
4/3+2x=42/5
2x=42/5-4/3
2x=106/15
x=106/15*1/2
x=53/15
therefore remaining equal side is 53/15
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