The base of an isoceles triangle measures 24cm ans its area is 60cm^2 find its perimeter
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Here is your answer...✌
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Let the height be h
Given that,
Base of traingle, b = 24cm
And,
Area of triangle = 60 cm²
(1/2)×b×h = 60
(1/2)×24×h = 60
h = 60×2/24
h = 5 cm
Now, using Pythagoras theorem other two sides of isoceles traingle which are equal
= √(12²+5²) = √169 = 13cm
Now,
Perimeter = 13+13+24 = 26+24 = 50cm
Here is your answer...✌
==============================
Let the height be h
Given that,
Base of traingle, b = 24cm
And,
Area of triangle = 60 cm²
(1/2)×b×h = 60
(1/2)×24×h = 60
h = 60×2/24
h = 5 cm
Now, using Pythagoras theorem other two sides of isoceles traingle which are equal
= √(12²+5²) = √169 = 13cm
Now,
Perimeter = 13+13+24 = 26+24 = 50cm
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