"The base of an isosceles right triangle is 30 cm. Its area is?" i think this q is incomplete. pls tell the Answer also of it isn't. pls
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[sorry guys it have become lengthy just bcoz of explanation of questions is done in detail.]
Let ABC be the right angel isosceles triangle
AB =perpendicular
BC= base of right angle
AC= hypotenuse of
right angle triangle
and
base of isosceles triangle
So ATQ,
AB=BC='X'cm (let AB & BC be "x")
By
Pythagoras Theorem,
hypotenuse = base square + perpendicular square.
H^2=P^2+B^2
X^2 + X^2 = 30^2
X=21.21 CM (approx.)
here,
[perpendicular and base are equal to each other]
Now,
area of triangle = half * base * height.
height and base, AB = BC =21. 21 cm
Area of = 1/2*b*h
=> 1/2*21.21*21.21
=> 224.91 cm^2
[ " * " means multiple ]
Let ABC be the right angel isosceles triangle
AB =perpendicular
BC= base of right angle
AC= hypotenuse of
right angle triangle
and
base of isosceles triangle
So ATQ,
AB=BC='X'cm (let AB & BC be "x")
By
Pythagoras Theorem,
hypotenuse = base square + perpendicular square.
H^2=P^2+B^2
X^2 + X^2 = 30^2
X=21.21 CM (approx.)
here,
[perpendicular and base are equal to each other]
Now,
area of triangle = half * base * height.
height and base, AB = BC =21. 21 cm
Area of = 1/2*b*h
=> 1/2*21.21*21.21
=> 224.91 cm^2
[ " * " means multiple ]
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