Question

The base of an isosceles traingle in 12 cm and its perimeter is 32 cm find its area

Answer 1

Perimetre = sum of 3sides in a triangle
32=x+x+12 ( let x as equal sides)
32= 2x+12

2x=32-12
x=10 cm
Height bisects the base at right angle so
h^2= p^2-b^2 (pathagorean theorem)
h^2=10^2-5^2
h^2= 100-25
h=8.66cm
Area =1/2base × height
1/2×8.66×12=4.33×12=51.96cm square.