the base of an isosceles triangle is 12 cm and its perimeter is 32 cm.Find its area
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Let x be the equal side.
==>Perimeter:2x+12=32.
x=10cm.
Height of the base=8 (by solving using Pythagorean theorem).
Area of triangle=1/2*b*h.
Area of triangle =1/2*12*8.
Area of triangle=48cm^2.
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