The base of an isosceles triangle is 12 cm.the perimeter is 32cm.find its area pls solve it by step by step method
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32=12+x+x
32=12+2x
32-12=2x
20=2x
X=20/2
X=10cm
The height of the triangle is 8cm by using pythagores property.
Area of triangle =1/2*base*height
=1/2*12*8
=48cm2 //
32=12+2x
32-12=2x
20=2x
X=20/2
X=10cm
The height of the triangle is 8cm by using pythagores property.
Area of triangle =1/2*base*height
=1/2*12*8
=48cm2 //
Taniskq13:
thank a lot
it's ok
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