The base of an isosceles triangle is 12cm and its perimeter is 32cm. Find its area.
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Answer:
length of base=12 cm
let the length of two equal sides be x cm
perimeter=32cm
b. t. p
x+x+12=32
2x=32-12
2x=20
x=10
altitude=√[(10) ^2+(6(^2]
√[100+36]
=√136=11.6
area=1/2 X 11.6 X 12
11.6X 6
69.6
abs 69.6sq.cm
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