the base of an isosceles triangle is 12cm and its perimeter is 32cm find the area of the triangle
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so the triangle is isosceles than two sides are equal, perimeter of triangle =32 let side=x than 32=x+x+12 so x=10 now by herons formula s=10+10+12/2=16 now √16(16-10)(16-10)(16-12)=√16×√6×√6×√4=24√4cmsqaure thanks hope it will help you
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