the base of an isosceles triangle is 12cm and its perimeter is 32cm find its area
Answers
Answered by
45
Other 2 sides
2x+12=32
2x=32-12
x=10
Height using pythagoras theorem
Then it will come 8
In this way
Let x be height
x²=100-36
x²=64
x=8
Area=1/2×base× height
=1/2×12×8
=48 cm ²
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2x+12=32
2x=32-12
x=10
Height using pythagoras theorem
Then it will come 8
In this way
Let x be height
x²=100-36
x²=64
x=8
Area=1/2×base× height
=1/2×12×8
=48 cm ²
Happy New year
If u like my answer mark it as a brainlist
kshitijNGU:
of it helped you can you please mark it as a brainlist
Answered by
6
a+b+c=32,a+a+12=32,2a=32-12=20,a=20/2=10,area=root s(s-a)(s-b)(s-c),s=a+b+c/2=10+10+12=32/2=16
root[
16(16-10)(16-10)(16-12)],root(16*6*6*4),root(2304)=48cm^2
root[
16(16-10)(16-10)(16-12)],root(16*6*6*4),root(2304)=48cm^2
if u like mark it as brainliest.plz.happy new year.
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