Question

the base of an isosceles triangle is 16 cm and its area is 48 . the perimeter of area is​

Answer 1

Answer:

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Let. ABC is an isosceles triangle whose base BC=16 cm . draw a perpendicular

AD on BC.

Area of triangle ABC. = 1/2×AD×BC

=1/2×AD×16

=8×AD

8×AD=48=> AD=6 cm

In right angled triangle ADC

AC²= AD²+DC²

AC²=(6)²+(16/2)². => AC²=100. or. AC = 10 cm

Perimeter of triangle ABC =AB+BC+CA=10+16+10 = 36 cms.

Answer 2

Answer:

Answer:

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AnSWer

Let. ABC is an isosceles triangle whose base BC=16 cm . draw a perpendicular

AD on BC.

Area of triangle ABC. = 1/2×AD×BC

=1/2×AD×16

=8×AD

8×AD=48=> AD=6 cm

In right angled triangle ADC

AC²= AD²+DC²

AC²=(6)²+(16/2)². => AC²=100. or. AC = 10 cm

Perimeter of triangle ABC =AB+BC+CA=10+16+10 = 36 cms.