Question

the base of an isosceles triangle is 2 cm. the perimeter of the triangle is 10 cm.​ find the length of the equal sides

Answer 1

$\large{\mathfrak{\underline{\underline{\red{Answer:-}}}}}$

Equal sides are of 4cm each

${\mathfrak{\underline{\underline{\purple{Step-By-Step-Explanation:-}}}}}$

✯ Base = 2cm

✯ Perimeter = 10cm

$\large\mathtt{\green{Let \: the \: equal \: sides \: be \: x}}$

➭ We know that :-

$\Large{\boxed{\boxed{\mathbf{\orange{Perimeter \: of \: {\triangle} \: = \: Sum \: of \: sides}}}}}$

______________[Put Values]

⇒ 10 = x + x + 2

⇒ 2x = 10-2

⇒ 2x = 8

⇒ x = 8/2

⇒ x = 4cm

So, sides of Δ are 4cm, 4cm, and 2cm

$\rule{200}{2}$

$\large{\mathfrak{\underline{\blue{Verification:-}}}}$

Perimeter = Sum of sides

⇒ 10 = 2 + 4 + 4

⇒ 10 = 8 + 2

⇒ 10 = 10

Answer 2

Answer:

4cm

Step-by-step explanation:

We're going to solve this using just one variable!

Let's assume that the equal sides are x cm long

What else do we know about the triangle?

The perimeter of the triangle is 10 cm

2+x+x=10

2x

2x

x

​

 

=10

=10−2

=8

=4

​