The base of an isosceles triangle is 24 cm and its area is 192 Sq. cm. find its perimeter.
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Answered by
7
area of triangle=1/2*base*height
height=(2*192)/24
=16
So side=hypotenuse=x
x square=12square+16square
x square=400
x=√400
x=20
In an isosceles triangle the sides excluding the base are equal.
So perimeter=20+20+24
=64
height=(2*192)/24
=16
So side=hypotenuse=x
x square=12square+16square
x square=400
x=√400
x=20
In an isosceles triangle the sides excluding the base are equal.
So perimeter=20+20+24
=64
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14
see the image for soln.
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