the base of an isosceles triangle is 24 cm and its area is 192 sq. cm . find its area
shreya32457:
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Area is already given
1/2*b*h=192
h=2*192/24=16
equal side^2=(16^2)+(12^2)
Eq. side =20
perimeter =2(20)+24
=64
1/2*b*h=192
h=2*192/24=16
equal side^2=(16^2)+(12^2)
Eq. side =20
perimeter =2(20)+24
=64
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