Question

*The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4
cm. What is the length of either of the remaining equal sides?​

Answer 1

Answer:

let the two sides of isocles triangle be x

x+x+4/3=4

2x=4-4/3

2x=8/3

x=4/3

Answer 2

Given :

• The base of an isosceles triangle is 4/3 cm
• The perimeter of the triangle is 4 cm.

To Find :

• Length of the remaining 2 sides.

Solution :

Since, the triangle is an isosceles triangle, we know that the two of the three sides will be equal in length.

Let the equal sides of the triangle be x cm.

The base i.e 3rd side is 4/3 cm.

•°• 3rd side = $\sf{\dfrac{4}{3}\:cm\:\:\:(i)}$

Provided, perimeter = 4 cm.

We know perimeter is the sum of all sides.

Applying the formula of perimeter,

$\longrightarrow$ $\sf{x+x+\dfrac{4}{3}\:=\:4}$

$\longrightarrow$ $\sf{2x+\dfrac{4}{3}=4}$

$\longrightarrow$ $\sf{\dfrac{6x+4}{3}=4}$

$\longrightarrow$ $\sf{6x+4=12}$

$\longrightarrow$ $\sf{6x=12-4}$

$\longrightarrow$ $\sf{6x=8}$

$\longrightarrow$ $\sf{x=\dfrac{8}{6}}$

$\longrightarrow$ $\sf{x=\dfrac{4}{3}}$

Two equal sides of the triangle, x is 4/3 cm i.e 1.33 cm.

$\large{\boxed{\sf{\purple{Remaining\:side\:=x\:=\:1.33 \:cm}}}}$

$\large{\boxed{\sf{\purple{Third\:side\:=\:1.33\:cm}}}}$