Question

the base of an isosceles triangle is 4/3cm.the perimeter of the triangle is 2/15 and whole number 4cm.what is the length of either of the remaining equal sides? ​

Answer 1

Step-by-step explanation:

Base=4/3cm

Let the equal sides be x.

Perimeter=S1+S2+S3

62/15=x+x+4/3

62/15=2x+4/3

62/15-4/3=2x

(62-20)/15=2x

42/15/2=x

42/15×1/2=x

21/15=x

7/5=x

Thus,

Two equal sides = x = 7/5cm

Answer 2

Answer:

let one side be x cm, so, the other one is x cm, as well. So, 2x+4/3= 62/15.

(6x+4)/3=62/15.

6x+4=62/5.

30x+20=62.

30x=52

x=52/30, x=21/15. Therefore, x=7/5

so, the equal sides r 7/5cm, respectively...

Thank u...