Question

The base of an isosceles triangle is 4/5 cm, what is length of remaining equal sides?​

Answer 1

Answer:

Let the length of equal sides be x cm. Perimeter = x cm + x cm + Base = 4 2/15 cm 2x + 4/3 = 62/15 On transposing 4/3 to R.H.S, we obtain 2x = 62/15 - 4/3 2x = 62 - 4 x 5/15 = 62 - 20/15 2x = 42/15 On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5 Therefore, the length of equal sides is 1 2/5 c m.Read more on Sarthaks.com - https://www.sarthaks.com/105680/base-isosceles-triangle-perimeter-triangle-what-length-either-the-remaining-equal-sides

Answer 2

Answer:

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