Question

The base of an isosceles triangle is 6 cm and each of its equal sides are s 5 cm. The height of the triangle is

Answer 1

Detailed Solution:

This question just requires knowledge of area and the legendary Heron's Formula.

So, let's begin

So, we're given base = 6 cm and other two sides of that triangle = 5 cm.

So, let's ask ourselves the area

This is calculated by Heron's formula:-

                     Area =  $\sqrt{s(s-a)(s-b)(s-c)}$

                             where s is the semi perimeter.

So, Area for this isosceles triangle = $\sqrt{8(8-6)(8-5)(8-5)}$ $= 12 sq. cm$

Now taking the 6 cm length as base, let height be h.

(You can ignore this part if you haven't yet took Trigonometric class)

Therefore, again the simplest ever formula is $\frac{1}{2} l b sin\alpha$, where l,b are the sides and α is the angle.

(In this case $\alpha = 90$ degrees, so $sin\alpha$ = 1)

But area is also equal to 12 sq cm.

Therefore, $12 = \frac{1}{2} h*5$

      Solving we get, h = $\frac{24}{5}$

Do ask me for any doubts and if you like my efforts then you can mark me as brainliest.

Answer 2

Answer:

4cm is the answer of this question