The base of an isosceles triangle is 6cm and its perimeter is 16 cm . Length of each of the equal side is ??
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Answered by
6
Let the length of each equal side be x.
Since, perimeter of a ∆ = sum of its all sides
Therefore, from the question we have
x +x +6 cm = 16 cm
x = 5cm.
Hence, the length of each equal side is 5 cm.
Since, perimeter of a ∆ = sum of its all sides
Therefore, from the question we have
x +x +6 cm = 16 cm
x = 5cm.
Hence, the length of each equal side is 5 cm.
Answered by
2
as we know that
perimeter is sum of the all sides
so sum of all sides of triangle is 16
6 +b+c =16
6 +b+b=16 (isoscels triangle has two equal sides)
6+2b=16
2b=16-6 =10
b=10/2=5
hope this is helpful for you
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perimeter is sum of the all sides
so sum of all sides of triangle is 16
6 +b+c =16
6 +b+b=16 (isoscels triangle has two equal sides)
6+2b=16
2b=16-6 =10
b=10/2=5
hope this is helpful for you
mark me as brainlist please
Anonymous:
please mark me brainlist
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