The base of an isosceles triangle measure 24cm and it's area is 192 cm find its perimeter
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Answered by
8
first find its height like this
area= 1/2*b*h
let h be h
192=1/2*24*h
192=12*h
192/12=h
16=h
so now we have find h
now we can find perimeter
p =2*(l+b)
p=2*40
p= 80
area= 1/2*b*h
let h be h
192=1/2*24*h
192=12*h
192/12=h
16=h
so now we have find h
now we can find perimeter
p =2*(l+b)
p=2*40
p= 80
Answered by
4
now,
you can find the perimeter by using formula-
2a+B
2(20)+24
40+24
64.
you can find the perimeter by using formula-
2a+B
2(20)+24
40+24
64.
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