Question

The base of an isosceles triangle measures 24cm and its area is 60cm sq. find its perimeter?

Answer 1

b=24cm , h=??
area=60 cm^2
1/2*b*h=60cm^2
1/2*24*h=60
h=60*2/24=120/24=5cm
By Pythagoras theorem,
Hypotenuse^2=base^2+perpendicular^2
h^2=b^2+p^2
h= whole under root b^2+p^2
h=whole under root 24^2+5^2
h=whole under root 576+25
h=under root 601
h=24.515301........
h=24 cm........(approx)
So, base=24cm
common sides=24 cm
Perimeter=Sum of all sides
24+24+24=72cm

Answer 2

Answer:

Step-by-step explanation:

b=24cm , h=??

area=60 cm^2

1/2*b*h=60cm^2

1/2*24*h=60

h=60*2/24=120/24=5cm

By Pythagoras theorem,

Hypotenuse^2=base^2+perpendicular^2

h^2=b^2+p^2

h= whole under root b^2+p^2

h=whole under root 24^2+5^2

h=whole under root 576+25

h=under root 601

h=24.515301........

h=24 cm........(approx)

So, base=24cm

common sides=24 cm

Perimeter=Sum of all sides

24+24+24=72cm