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The base of an isosceles triangle measures 80 cm and its area is 360 con?
Find the perimeter of the triangle.
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Area of triangle =
2
1
×base×height=360 sq cm
2
1
×80×height=360
=> height =9 cm.
Since the height of the triangle, divides it into two right angled triangles,
a
2
=h
2
+(
2
b
)
2
=>a
2
=9
2
+(
2
80
)
2
=1681
Hence, a=41 cm.
Perimeter of the triangle = Sum of all sides = a + a + b =41+41+80=162cm
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