the base of an isosceles triangle measures 80cm and it's area is 360cm2. find the perimeter of the triangle.
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Answered by
47
I hope this helps you!!
Vaibhav
Vaibhav
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nitya28:
thanks dear
nice answer
thanks anisha
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Answered by
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Hi there!
Let us consider the Equal sides to be = x
by Pythagoras Theorem :-
Height, h = √x² - 40² = √x² - 1600
Given :-
Area if Triangle = 360
1 / 2 × 80 × √x² - 1600 = 360
40 × √x² - 1600 = 360
√x² - 1600 = 360 / 40
√x² - 1600 = 9
x² - 1600 = 81
x² = 1681
x = √1681 = 41
Therefore,
Perimeter of Triangle = 2x + 80
= 2 × 41 + 80
= 82 + 80
= 162 cm
Hence, The required answer is :-
Perimeter of Triangle = 162 cm
Hope it helps! :)
Let us consider the Equal sides to be = x
by Pythagoras Theorem :-
Height, h = √x² - 40² = √x² - 1600
Given :-
Area if Triangle = 360
1 / 2 × 80 × √x² - 1600 = 360
40 × √x² - 1600 = 360
√x² - 1600 = 360 / 40
√x² - 1600 = 9
x² - 1600 = 81
x² = 1681
x = √1681 = 41
Therefore,
Perimeter of Triangle = 2x + 80
= 2 × 41 + 80
= 82 + 80
= 162 cm
Hence, The required answer is :-
Perimeter of Triangle = 162 cm
Hope it helps! :)
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